Working with Fractions Class 7 Extra Questions Maths Chapter 8

During revision, students quickly go through Class 7 Maths Extra Questions Chapter 8 Working with Fractions Class 7 Extra Questions with Answers for clarity.

Class 7 Working with Fractions Extra Questions

Class 7 Maths Chapter 7 Working with Fractions Extra Questions

Class 7 Maths Chapter 8 Extra Questions – Working with Fractions Extra Questions Class 7

Question 1.
Multiply.
(a) \(\frac{5}{19} \times \frac{18}{7}\)
Solution:
\(\frac{5}{19} \times \frac{18}{7}=\frac{5 \times 18}{19 \times 7}\)
= \(\frac{90}{133}\)

(b) \(\frac{15}{16} \times \frac{12}{7} \times \frac{119}{75}\)
Solution:

\(\frac{3 \times 17}{4 \times 5}=\frac{51}{20}=2 \frac{11}{20}\)

Question 2.
Each side of a square iron sheet is 1 \(\frac{3}{8}\) m. Find its area.
Solution:
Area of a square sheet = side x side = 1 \(\frac{3}{8}\) × 1 \(\frac{3}{8}\)
= \(\frac{11}{8} \times \frac{11}{8}=\frac{121}{64}\)
= 1\( sq. m
Hence, the area of the square iron sheet is 1[latex\frac{57}{64}\) sq. m.

Question 3.
The cost of 1 kg of flour is ₹ 21\(\frac{1}{2}\). Find the cost of 6\(\frac{1}{2}\) kg of flour.
Solution:
Cost of 1 kg of flour = ₹ 21 \(\frac{1}{2}\) = ₹ \(\frac{43}{2}\)
So, cost of 6 \(\frac{1}{2}\) kg of flour = ₹ \(\frac{43}{2}\) x 6\(\frac{1}{2}\)
= ₹ \(\frac{43}{2}\) × \(\frac{13}{2}\)
= \(\frac{13}{2}\)
= ₹ 139 \(\frac{3}{4}\)
Therefore, the cost of 6 \(\frac{1}{2}\) kg flour is ₹ 139 \(\frac{3}{4}\).

Question 4.
Divide
(a) 4 \(\frac{5}{6}\) ÷ 29
Solution:
4 \(\frac{5}{6}\) ÷ 29
= \(\frac{29}{6} \div \frac{29}{1}\)
= \(\frac{29}{6} \times \frac{1}{29}\)
= \(\frac{1}{6}\)

(b) 3\(\frac{5}{7}\) ÷ \(\frac{14}{15}\)
Solution:

(c) 20 + \(\frac{8}{11}\)
Solution:

Question 5.
Divide the sum of \(\frac{4}{7}\) and \(\frac{1}{7}\) by \(\frac{9}{7}\).
Solution:
\(\left(\frac{4}{7}+\frac{1}{7}\right) \div \frac{9}{7}=\frac{5}{7} \div \frac{9}{7}\)
= \(\frac{5}{7} \times \frac{7}{9}=\frac{5}{9}\)
= \(\frac{1}{2}\)

Question 6.
Reduce the following fractions into their simplest form.
(a) \(\frac{132}{148}\)
Solution:

[∵ 2 × 2 is the common factor of 132 and 148]
Thus, \(\frac{33}{37}\) is the simplest form of \(\frac{132}{148}\).

(b) \(\frac{145}{200}\)
Solution:

[∵ 5 is the common factor of 145 and 200]
Thus, \(\frac{29}{40}\) is the simplest form of .

Question 7.
Insert a number in ____ so that \(\frac{3}{4} \times \frac{2}{7}\) = ____. Out of all three fractions, which one is greatest?
Solution:

Out of the three fractions, \(\frac{3}{4}\) is the greatest.

Question 8.
A machine can print \(\frac{13}{4}\) pages in one minute. How many minutes will it take to print \(\frac{104}{4}\) pages?
Solution:
Number of minutes required to print \(\frac{104}{2}\) pages
= \(\frac{\frac{104}{4}}{\frac{13}{4}}\)
= \(\frac{104}{4} \times \frac{4}{13}\)
= 8

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